3.16.30 \(\int \frac {(a+b x)^{7/6}}{(c+d x)^{25/6}} \, dx\)

Optimal. Leaf size=66 \[ \frac {36 b (a+b x)^{13/6}}{247 (c+d x)^{13/6} (b c-a d)^2}+\frac {6 (a+b x)^{13/6}}{19 (c+d x)^{19/6} (b c-a d)} \]

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Rubi [A]  time = 0.01, antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {45, 37} \begin {gather*} \frac {36 b (a+b x)^{13/6}}{247 (c+d x)^{13/6} (b c-a d)^2}+\frac {6 (a+b x)^{13/6}}{19 (c+d x)^{19/6} (b c-a d)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^(7/6)/(c + d*x)^(25/6),x]

[Out]

(6*(a + b*x)^(13/6))/(19*(b*c - a*d)*(c + d*x)^(19/6)) + (36*b*(a + b*x)^(13/6))/(247*(b*c - a*d)^2*(c + d*x)^
(13/6))

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*Simplify[m + n + 2])/((b*c - a*d)*(m + 1)), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rubi steps

\begin {align*} \int \frac {(a+b x)^{7/6}}{(c+d x)^{25/6}} \, dx &=\frac {6 (a+b x)^{13/6}}{19 (b c-a d) (c+d x)^{19/6}}+\frac {(6 b) \int \frac {(a+b x)^{7/6}}{(c+d x)^{19/6}} \, dx}{19 (b c-a d)}\\ &=\frac {6 (a+b x)^{13/6}}{19 (b c-a d) (c+d x)^{19/6}}+\frac {36 b (a+b x)^{13/6}}{247 (b c-a d)^2 (c+d x)^{13/6}}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 46, normalized size = 0.70 \begin {gather*} \frac {6 (a+b x)^{13/6} (-13 a d+19 b c+6 b d x)}{247 (c+d x)^{19/6} (b c-a d)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^(7/6)/(c + d*x)^(25/6),x]

[Out]

(6*(a + b*x)^(13/6)*(19*b*c - 13*a*d + 6*b*d*x))/(247*(b*c - a*d)^2*(c + d*x)^(19/6))

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IntegrateAlgebraic [A]  time = 0.18, size = 51, normalized size = 0.77 \begin {gather*} \frac {6 (a+b x)^{13/6} \left (19 b-\frac {13 d (a+b x)}{c+d x}\right )}{247 (c+d x)^{13/6} (b c-a d)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(a + b*x)^(7/6)/(c + d*x)^(25/6),x]

[Out]

(6*(a + b*x)^(13/6)*(19*b - (13*d*(a + b*x))/(c + d*x)))/(247*(b*c - a*d)^2*(c + d*x)^(13/6))

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fricas [B]  time = 1.34, size = 235, normalized size = 3.56 \begin {gather*} \frac {6 \, {\left (6 \, b^{3} d x^{3} + 19 \, a^{2} b c - 13 \, a^{3} d + {\left (19 \, b^{3} c - a b^{2} d\right )} x^{2} + 2 \, {\left (19 \, a b^{2} c - 10 \, a^{2} b d\right )} x\right )} {\left (b x + a\right )}^{\frac {1}{6}} {\left (d x + c\right )}^{\frac {5}{6}}}{247 \, {\left (b^{2} c^{6} - 2 \, a b c^{5} d + a^{2} c^{4} d^{2} + {\left (b^{2} c^{2} d^{4} - 2 \, a b c d^{5} + a^{2} d^{6}\right )} x^{4} + 4 \, {\left (b^{2} c^{3} d^{3} - 2 \, a b c^{2} d^{4} + a^{2} c d^{5}\right )} x^{3} + 6 \, {\left (b^{2} c^{4} d^{2} - 2 \, a b c^{3} d^{3} + a^{2} c^{2} d^{4}\right )} x^{2} + 4 \, {\left (b^{2} c^{5} d - 2 \, a b c^{4} d^{2} + a^{2} c^{3} d^{3}\right )} x\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(7/6)/(d*x+c)^(25/6),x, algorithm="fricas")

[Out]

6/247*(6*b^3*d*x^3 + 19*a^2*b*c - 13*a^3*d + (19*b^3*c - a*b^2*d)*x^2 + 2*(19*a*b^2*c - 10*a^2*b*d)*x)*(b*x +
a)^(1/6)*(d*x + c)^(5/6)/(b^2*c^6 - 2*a*b*c^5*d + a^2*c^4*d^2 + (b^2*c^2*d^4 - 2*a*b*c*d^5 + a^2*d^6)*x^4 + 4*
(b^2*c^3*d^3 - 2*a*b*c^2*d^4 + a^2*c*d^5)*x^3 + 6*(b^2*c^4*d^2 - 2*a*b*c^3*d^3 + a^2*c^2*d^4)*x^2 + 4*(b^2*c^5
*d - 2*a*b*c^4*d^2 + a^2*c^3*d^3)*x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (b x + a\right )}^{\frac {7}{6}}}{{\left (d x + c\right )}^{\frac {25}{6}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(7/6)/(d*x+c)^(25/6),x, algorithm="giac")

[Out]

integrate((b*x + a)^(7/6)/(d*x + c)^(25/6), x)

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maple [A]  time = 0.00, size = 54, normalized size = 0.82 \begin {gather*} -\frac {6 \left (b x +a \right )^{\frac {13}{6}} \left (-6 b d x +13 a d -19 b c \right )}{247 \left (d x +c \right )^{\frac {19}{6}} \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^(7/6)/(d*x+c)^(25/6),x)

[Out]

-6/247*(b*x+a)^(13/6)*(-6*b*d*x+13*a*d-19*b*c)/(d*x+c)^(19/6)/(a^2*d^2-2*a*b*c*d+b^2*c^2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (b x + a\right )}^{\frac {7}{6}}}{{\left (d x + c\right )}^{\frac {25}{6}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(7/6)/(d*x+c)^(25/6),x, algorithm="maxima")

[Out]

integrate((b*x + a)^(7/6)/(d*x + c)^(25/6), x)

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mupad [B]  time = 0.91, size = 189, normalized size = 2.86 \begin {gather*} -\frac {{\left (c+d\,x\right )}^{5/6}\,\left (\frac {\left (78\,a^3\,d-114\,a^2\,b\,c\right )\,{\left (a+b\,x\right )}^{1/6}}{247\,d^4\,{\left (a\,d-b\,c\right )}^2}-\frac {36\,b^3\,x^3\,{\left (a+b\,x\right )}^{1/6}}{247\,d^3\,{\left (a\,d-b\,c\right )}^2}-\frac {x^2\,\left (114\,b^3\,c-6\,a\,b^2\,d\right )\,{\left (a+b\,x\right )}^{1/6}}{247\,d^4\,{\left (a\,d-b\,c\right )}^2}+\frac {12\,a\,b\,x\,\left (10\,a\,d-19\,b\,c\right )\,{\left (a+b\,x\right )}^{1/6}}{247\,d^4\,{\left (a\,d-b\,c\right )}^2}\right )}{x^4+\frac {c^4}{d^4}+\frac {4\,c\,x^3}{d}+\frac {4\,c^3\,x}{d^3}+\frac {6\,c^2\,x^2}{d^2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)^(7/6)/(c + d*x)^(25/6),x)

[Out]

-((c + d*x)^(5/6)*(((78*a^3*d - 114*a^2*b*c)*(a + b*x)^(1/6))/(247*d^4*(a*d - b*c)^2) - (36*b^3*x^3*(a + b*x)^
(1/6))/(247*d^3*(a*d - b*c)^2) - (x^2*(114*b^3*c - 6*a*b^2*d)*(a + b*x)^(1/6))/(247*d^4*(a*d - b*c)^2) + (12*a
*b*x*(10*a*d - 19*b*c)*(a + b*x)^(1/6))/(247*d^4*(a*d - b*c)^2)))/(x^4 + c^4/d^4 + (4*c*x^3)/d + (4*c^3*x)/d^3
+ (6*c^2*x^2)/d^2)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**(7/6)/(d*x+c)**(25/6),x)

[Out]

Timed out

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